GD and Image 函数
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imagecolorresolve

(PHP 4, PHP 5)

imagecolorresolve — 取得指定颜色的索引值或有可能得到的最接近的替代值

说明

int imagecolorresolve ( resource $image , int $red , int $green , int $blue )

本函数可以保证对所请求的颜色返回一个颜色索引，要么是确切值要么是所能得到最接近的替代值。

如果从文件创建了图像，只有图像中使用了的颜色会被辨析。仅出现在调色板中的颜色不会被辨析。

参见 imagecolorclosest()。

GD and Image 函数
在线手册：中文 英文
PHP手册
PHP手册 - N: 取得指定颜色的索引值或有可能得到的最接近的替代值

用户评论:

ceo at l-i-e dot com (03-Jan-2002 11:55)

Okay, so sometimes it's really IMPORTANT to get the exact color you want, only it's not *IN* the Image, and ImageColorResolve just isn't "close enough".

The following code is a disgustingly gross hack, rather slow, but it does that.

$colorcount = array();
for ($x = 0; $x < $width; $x++){
    for ($y = 0; $y < $height; $y++){
        $colorindex = imagecolorat($jpg, $x, $y);
        if (!isset($colorcount[$colorindex])){
            $colorcount[$colorindex] = 1;
        }
        else{
            $colorcount[$colorindex]++;
        }
    }
}
asort($colorcount);
reset($colorcount);

$black = imagecolorexact($jpg, 0, 0, 0);
if ($black == -1){
    $goner = key($colorcount);
    $rgb = imagecolorsforindex($jpg, $goner);
    #error_log("Need black: About to kill $goner ($rgb[red], $rgb[green], $rgb[blue]) which was only used in $colorcount[$goner] pixels", 0);
    unset($colorcount[$goner]);
    imagecolordeallocate($jpg, $goner);
    $black = imagecolorallocate($jpg, 0, 0, 0);
}
if ($black == -1){
    $black = imagecolorresolve($jpg, 0, 0, 0);
    #error_log("Damn!  STILL couldn't allocate the color!", 0);
}