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jdtounix

(PHP 4, PHP 5)

jdtounix — 转变Julian Day计数为一个Unix时间戳

说明

int jdtounix ( int $jday )

这个函数根据给定的julian天数返回一个Unix时间戳，或如果参数jday不在Unix时间（Gregorian历法的1970年至2037年，或2440588 <= jday <= 2465342）范围内返回 FALSE 。返回的时间是本地时间（不是GMT）。

参数

jday

一个在 2440588 到 2465342 之间的julian天数

返回值

指定的julian天数的开始时的时间戳。

参见

Calendar 函数
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PHP手册 - N: 转变Julian Day计数为一个Unix时间戳

用户评论:

hrabi at linuxwaves dot com (29-Mar-2007 03:16)

Beware, jd here is not (astronomical or geocentric) Julian Day (JD), but Chronological Julian Day (CJD)! When JD start at noon of UTC time (12:00 UTC), CJD start at midnight at *local* time! Or considering head "Chronlogical Julian Day/Date" at "http://www.decimaltime.hynes.net/dates.html", when day localy start (it should be at sunset for instance).

try this...
<?php
define("UJD", 2440587.5);
define("SEC4DAY", 86400);

function u2j($tm) {
   return $tm / SEC4DAY + UJD;
}

function mmd($txt, $str_time) {
   $t = strtotime($str_time);
   $j = unixtojd($t);
   $j_fabio = u2j($t);
   $s = strftime('%D %T %Z', $t);

   printf("${txt} => %s, CJD: %s, JD: %s<br>\n", $s, $j, $j_fabio);
}

$xt = strtotime("1.1.1970 0:00.00 GMT");
$slb = "-1 day 23:30"; // let CJD be N
$sla = "0:30.00"; // should be N+1
$slm = "0:00"; // should be N+1
$sgmt = "0:00.00 GMT"; // don't forget to observe JD.

mmd("local before", $slb);
mmd("local after", $sla);
mmd("local midnight", $slm);
mmd("GMT midnight", $sgmt);
?>

I got this (you see, JD havn't change day, because UTC noon is far away):
local before => 03/28/07 23:30:00 CEST, CJD: 2454188, JD: 2454188.39583
local after => 03/29/07 00:30:00 CEST, CJD: 2454189, JD: 2454188.4375
local midnight => 03/29/07 00:00:00 CEST, CJD: 2454189, JD: 2454188.41667
GMT midnight => 03/29/07 02:00:00 CEST, CJD: 2454189, JD: 2454188.5

erelsgl dot NOSPAM at cs dot technion dot ac dot il (19-Sep-2006 02:31)

Just to clarify the differences between the different methods to convert a date to a timestamp.

Suppose:

<?php
$x = JDToUnix(GregorianToJD(9,23,2006));
$y = strtotime('2006-09-23');
$z = (GregorianToJD(9,23,2006) - 2440587.5) * 86400;
?>

Then, on a machine whoze timezone is GMT-0400, we get the following results:
<?php
$x === 1158969600;
$y === 1158984000;  //  $x + 4 hours
$z === 1159012800;  //  $x + 12 hours
?>

fabio at llgp dot org (31-Aug-2006 10:14)

If you need an easy way to convert a decimal julian day to an unix timestamp you can use:

$unixTimeStamp = ($julianDay - 2440587.5) * 86400;

2440587.5 is the julian day at 1/1/1970 0:00 UTC
86400 is the number of seconds in a day

(27-Jan-2005 02:50)

Warning: the calender functions involving julian day operations seem to ignore the decimal part of the julian day count.

This means that the returned date is wrong 50% of the time, since a julian day starts at decimal .5 .  Take care!!

seb at carbonauts dot com (21-Oct-2003 08:10)

Remember that unixtojd() assumes your timestamp is in GMT, but jdtounix() returns a timestamp in localtime.

This fooled me a few times. 

So if you have:

$timestamp1 = time();
$timestamp2 = jdtounix(unixtojd($timestamp1));

Unless your localtime is the same as GMT, $timestamp1 will not equal $timestamp2.

pipian at pipian dot com (12-Jun-2003 05:29)

Remember that UNIX timestamps indicate a number of seconds from midnight of January 1, 1970 on the Gregorian calendar, not the Julian Calendar.