MySQL 函数
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mysql_field_table

(PHP 4, PHP 5)

mysql_field_table 取得指定字段所在的表名

说明

string mysql_field_table ( resource $result , int $field_offset )

返回指定字段所在的表的名字。

为向下兼容仍然可以使用 mysql_fieldtable(),但反对这样做。


MySQL 函数
在线手册:中文 英文
PHP手册
PHP手册 - N: 取得指定字段所在的表名

用户评论:

mehdi dot haresi at gmail dot com (17-Jul-2009 10:50)

For all of you having problems accessing duplicated field names in queries with their table alias i have implemented the following quick solution:

<?php
function mysql_fetch_alias_array($result)
{
    if (!(
$row = mysql_fetch_array($result)))
    {
        return
null;
    }

   
$assoc = Array();
   
$rowCount = mysql_num_fields($result);
   
    for (
$idx = 0; $idx < $rowCount; $idx++)
    {
       
$table = mysql_field_table($result, $idx);
       
$field = mysql_field_name($result, $idx);
       
$assoc["$table.$field"] = $row[$idx];
    }
   
    return
$assoc;
}
?>

Lets asume we have 2 tables student and contact each having fID as the index field and want to access both fID fields in php.

The usage of this function will be pretty similar to calling mysql_fetch_array:

<?php
$result
= mysql_query("select * from student s inner join contact c on c.fID = s.frContactID");

while (
$row = mysql_fetch_alias_array($result))
{
    echo
"StudenID: {$row['s.fID']}, ContactID: {$row['c.fID']}";
}
?>

Voila, that's it :)

Please be aware that by using this function, you have to access all fields with their alias name (e.g. s.Name, s.Birhtday) even if they are not duplicated.

If you have questions, just send me a mail.

Best regards,
Mehdi Haresi
die-webdesigner.at

jorge at rhst dot net (29-Jul-2007 10:57)

The function below takes a function and returns the col->table mapping as an array.

For example:

$query = “SELECT a.id AS a_id, b.id b_id FROM atable AS a, btable b”

$cols  = queryAlias($query);

print_r($cols);

Returns:

Array
(
    [a] => atable
    [b] => btable
)

I can't promise it's perfect, but this function never hit production cause I ended up using mysqli methods instead.

Enjoy
-Jorge

  /**
   * Takes in a query and returns the alias->table mapping.
   *
   * @param string $query
   * @return array of alias mapping
   */
 
  function queryAlias ( $query ) {
   
    //Make it all lower, we ignore case
    $substr = strtolower($query);
   
    //Remove any subselects
    $substr = preg_replace ( ‘/\(.*\)/’, ”, $substr);
  
    //Remove any special charactors
    $substr = preg_replace ( ‘/[^a-zA-Z0-9_,]/’, ‘ ‘, $substr);
   
    //Remove any white space
    $substr = preg_replace(‘/\s\s+/’, ‘ ‘, $substr);
   
    //Get everything after FROM
    $substr = strtolower(substr($substr, strpos(strtolower($substr),‘ from ‘) + 6));
   
    //Rid of any extra commands
    $substr = preg_replace(
                Array(
                    ‘/ where .*+$/’,
                    ‘/ group by .*+$/’,
                    ‘/ limit .*+$/’ ,
                    ‘/ having .*+$/’ ,
                    ‘/ order by .*+$/’,
                    ‘/ into .*+$/’
                   ), ”, $substr);
   
    //Remove any JOIN modifiers
    $substr = preg_replace(
                Array(
                    ‘/ left /’,
                    ‘/ right /’,
                    ‘/ inner /’,
                    ‘/ cross /’,
                    ‘/ outer /’,
                    ‘/ natural /’,
                    ‘/ as /’
                   ), ‘ ‘, $substr);
   
    //Replace JOIN statements with commas
    $substr = preg_replace(Array(‘/ join /’, ‘/ straight_join /’), ‘,’, $substr);
   

    $out_array = Array();
   
    //Split by FROM statements
    $st_array = split (‘,’, $substr);
 
    foreach ($st_array as $col) {
     
      $col = preg_replace(Array(‘/ on .*+/’), ”, $col);
     
      $tmp_array = split(‘ ‘, trim($col));
     
      //Oh no, something is wrong, let’s just continue
      if (!isset($tmp_array[0]))
        continue;
       
      $first = $tmp_array[0];
     
      //If the “AS” is set, lets include that, if not, well, guess this table isn’t aliased.
      if (isset($tmp_array[1]))
        $second = $tmp_array[1];
        else 
        $second = $first;
       
      if (strlen($first))
       $out_array[$second] = $first;
     
    }
   
    return $out_array;
  }

spam at blondella dot de (03-Oct-2006 12:09)

<?php
/*
this function might help in the case described above :-)
*/
function mysql_field_table_resolve_alias($inQuery,$inResult,$inFieldName) {
  
$theNameOrAlias = mysql_field_table($inResult,$inFieldName);
  
//check, if AS syntax is being used
  
if(ereg(" AS ",$inQuery))  {
     
//catch words in query
     
$theWords = explode(" ",ereg_replace(",|\n"," ",$inQuery));
     
//find the words preceding and following AS
     
foreach($theWords as $theIndex => $theWord)  {
         if(
trim($theWord) == "AS"
        
&& isset($theWords[$theIndex-1])
         && isset(
$theWords[$theIndex+1])
         &&
$theWords[$theIndex+1] == $theNameOrAlias
        
) {
           
$theNameOrAlias = $theWords[$theIndex-1];
            break
1;
         }
      }
   }
   return
$theNameOrAlias;
}
?>

me at thomaskeller dot biz (23-Nov-2005 09:15)

Beware that if you upgrade to MySQL 5 from any earlier version WITHOUT dumping and reloading your data (just by keeping the binary data in MyISAM table files), you might get weird output on the "table" value for mysql_fetch_field and in this function. Weird means that the table name is randomly set or not.

This behaviour seems to popup only if the SQL query contains a ORDER BY clause. A bug is already reported:

http://bugs.mysql.com/bug.php?id=14915

To prevent the issue, dump and reload all participating tables in your query or do

CREATE TABLE tmp SELECT * FROM table;
DROP TABLE table;
ALTER TABLE tmp RENAME table;

on each one via commandline client.

cptnemo (15-Aug-2004 03:18)

When trying to find table names for a (My)SQL query containing 'tablename AS alias', mysql_field_table() only returns the alias as specified in the AS clause, and not the tablename.